Today’s exercise exercise will focus on different techniques of clustering and classification. I will use data on housing in areas of Boston and mostly focus on the crime rate in the city. The data can be accessed through the R library MASS. The data contains area-level information on the characteristics of homes (size, value etc.), the demographic composition of the area as well as several variables related to environmental and infrastructural factors. More information on the data is available here and in the original study by Harrison & Rubinfeld (1978).
BTW, I decided to hide my code chunks by default in this course diary as they make reading a bit tedious. You should be able to get the codes by clicking the Code-button next to results.
library(MASS)
library(tidyverse)
library(GGally)
library(corrplot)
data(Boston)
dim(Boston)
## [1] 506 14
str(Boston)
## 'data.frame': 506 obs. of 14 variables:
## $ crim : num 0.00632 0.02731 0.02729 0.03237 0.06905 ...
## $ zn : num 18 0 0 0 0 0 12.5 12.5 12.5 12.5 ...
## $ indus : num 2.31 7.07 7.07 2.18 2.18 2.18 7.87 7.87 7.87 7.87 ...
## $ chas : int 0 0 0 0 0 0 0 0 0 0 ...
## $ nox : num 0.538 0.469 0.469 0.458 0.458 0.458 0.524 0.524 0.524 0.524 ...
## $ rm : num 6.58 6.42 7.18 7 7.15 ...
## $ age : num 65.2 78.9 61.1 45.8 54.2 58.7 66.6 96.1 100 85.9 ...
## $ dis : num 4.09 4.97 4.97 6.06 6.06 ...
## $ rad : int 1 2 2 3 3 3 5 5 5 5 ...
## $ tax : num 296 242 242 222 222 222 311 311 311 311 ...
## $ ptratio: num 15.3 17.8 17.8 18.7 18.7 18.7 15.2 15.2 15.2 15.2 ...
## $ black : num 397 397 393 395 397 ...
## $ lstat : num 4.98 9.14 4.03 2.94 5.33 ...
## $ medv : num 24 21.6 34.7 33.4 36.2 28.7 22.9 27.1 16.5 18.9 ...
summary(Boston)
## crim zn indus chas
## Min. : 0.00632 Min. : 0.00 Min. : 0.46 Min. :0.00000
## 1st Qu.: 0.08205 1st Qu.: 0.00 1st Qu.: 5.19 1st Qu.:0.00000
## Median : 0.25651 Median : 0.00 Median : 9.69 Median :0.00000
## Mean : 3.61352 Mean : 11.36 Mean :11.14 Mean :0.06917
## 3rd Qu.: 3.67708 3rd Qu.: 12.50 3rd Qu.:18.10 3rd Qu.:0.00000
## Max. :88.97620 Max. :100.00 Max. :27.74 Max. :1.00000
## nox rm age dis
## Min. :0.3850 Min. :3.561 Min. : 2.90 Min. : 1.130
## 1st Qu.:0.4490 1st Qu.:5.886 1st Qu.: 45.02 1st Qu.: 2.100
## Median :0.5380 Median :6.208 Median : 77.50 Median : 3.207
## Mean :0.5547 Mean :6.285 Mean : 68.57 Mean : 3.795
## 3rd Qu.:0.6240 3rd Qu.:6.623 3rd Qu.: 94.08 3rd Qu.: 5.188
## Max. :0.8710 Max. :8.780 Max. :100.00 Max. :12.127
## rad tax ptratio black
## Min. : 1.000 Min. :187.0 Min. :12.60 Min. : 0.32
## 1st Qu.: 4.000 1st Qu.:279.0 1st Qu.:17.40 1st Qu.:375.38
## Median : 5.000 Median :330.0 Median :19.05 Median :391.44
## Mean : 9.549 Mean :408.2 Mean :18.46 Mean :356.67
## 3rd Qu.:24.000 3rd Qu.:666.0 3rd Qu.:20.20 3rd Qu.:396.23
## Max. :24.000 Max. :711.0 Max. :22.00 Max. :396.90
## lstat medv
## Min. : 1.73 Min. : 5.00
## 1st Qu.: 6.95 1st Qu.:17.02
## Median :11.36 Median :21.20
## Mean :12.65 Mean :22.53
## 3rd Qu.:16.95 3rd Qu.:25.00
## Max. :37.97 Max. :50.00
hist(Boston$crim)
The data includes 14 variables from some 500 regions in Boston. All of them are numeric.My main varibale of interest, crime rate, seems highly skewed, with most of the areas having low rates of crime and a have expressing higher rates.
p.values.mat <-cor.mtest(Boston,
conf.level = .95)
cor.mat <- cor(Boston)
corrplot.mixed(cor.mat,
lower.col='black',
upper='color',
tl.col='black',
tl.cex=0.5,
number.cex=0.5,
p.mat=p.values.mat$p,
sig.level=0.05)
Correlation plot
For a graphical overview of data, I am using the correlation plot to make the plot to some extent readable (as compared to pairs or ggpairs. In the plot, I have crossed out all the correlations not significant at 95% confidence level. Accordingly, it seems that the variable chas is not significantly correlated with most of the variables (probably as it is binary). Most of the other variables are, and there seems to be relatively strong correlations, for instance rad tax 0.91, age and dis -0.75, nox indus 0.76. Most of the correlations seem moderate, between 0.3 and 0.6.Rad and tax for crime rate.
#Scale boston data
boston_scaled <- as.data.frame(scale(Boston))
summary(boston_scaled)
## crim zn indus chas
## Min. :-0.419367 Min. :-0.48724 Min. :-1.5563 Min. :-0.2723
## 1st Qu.:-0.410563 1st Qu.:-0.48724 1st Qu.:-0.8668 1st Qu.:-0.2723
## Median :-0.390280 Median :-0.48724 Median :-0.2109 Median :-0.2723
## Mean : 0.000000 Mean : 0.00000 Mean : 0.0000 Mean : 0.0000
## 3rd Qu.: 0.007389 3rd Qu.: 0.04872 3rd Qu.: 1.0150 3rd Qu.:-0.2723
## Max. : 9.924110 Max. : 3.80047 Max. : 2.4202 Max. : 3.6648
## nox rm age dis
## Min. :-1.4644 Min. :-3.8764 Min. :-2.3331 Min. :-1.2658
## 1st Qu.:-0.9121 1st Qu.:-0.5681 1st Qu.:-0.8366 1st Qu.:-0.8049
## Median :-0.1441 Median :-0.1084 Median : 0.3171 Median :-0.2790
## Mean : 0.0000 Mean : 0.0000 Mean : 0.0000 Mean : 0.0000
## 3rd Qu.: 0.5981 3rd Qu.: 0.4823 3rd Qu.: 0.9059 3rd Qu.: 0.6617
## Max. : 2.7296 Max. : 3.5515 Max. : 1.1164 Max. : 3.9566
## rad tax ptratio black
## Min. :-0.9819 Min. :-1.3127 Min. :-2.7047 Min. :-3.9033
## 1st Qu.:-0.6373 1st Qu.:-0.7668 1st Qu.:-0.4876 1st Qu.: 0.2049
## Median :-0.5225 Median :-0.4642 Median : 0.2746 Median : 0.3808
## Mean : 0.0000 Mean : 0.0000 Mean : 0.0000 Mean : 0.0000
## 3rd Qu.: 1.6596 3rd Qu.: 1.5294 3rd Qu.: 0.8058 3rd Qu.: 0.4332
## Max. : 1.6596 Max. : 1.7964 Max. : 1.6372 Max. : 0.4406
## lstat medv
## Min. :-1.5296 Min. :-1.9063
## 1st Qu.:-0.7986 1st Qu.:-0.5989
## Median :-0.1811 Median :-0.1449
## Mean : 0.0000 Mean : 0.0000
## 3rd Qu.: 0.6024 3rd Qu.: 0.2683
## Max. : 3.5453 Max. : 2.9865
Tähän sössöä
#Save categories of crime rate
bins <- quantile(boston_scaled$crim)
#Create new crime variable
crime <- cut(boston_scaled$crim,
breaks=bins,
include.lowest=T,
label=c(
"low",
"med_low",
"med_high",
"high"))
boston_scaled$crim <- NULL
boston_scaled$crime <- crime
#Divide data into test and training sets
n <- nrow(boston_scaled)
#Randomly sample 80% of the original rows
#These are used for training
ind <- sample(n, size=n*0.8)
#Train set
train <- boston_scaled[ind,]
#Test set
test <- boston_scaled[-ind,]
#Correct classes in the test set
correct <- test$crime
#Drop crime from test
test <- dplyr::select(test, -crime)
#LDA model
lda.fit <-
lda(crime~., data=train)
lda.fit
## Call:
## lda(crime ~ ., data = train)
##
## Prior probabilities of groups:
## low med_low med_high high
## 0.2450495 0.2623762 0.2425743 0.2500000
##
## Group means:
## zn indus chas nox rm age
## low 1.0608843 -0.8978999 -0.11325431 -0.8914757 0.45663611 -0.9021716
## med_low -0.0659521 -0.3676836 -0.01233188 -0.5943789 -0.12104669 -0.3709187
## med_high -0.3892353 0.1419212 0.16959035 0.3893871 0.08829714 0.3925050
## high -0.4872402 1.0171306 -0.03844192 1.0559786 -0.40512004 0.8042585
## dis rad tax ptratio black lstat
## low 0.9280665 -0.6930143 -0.7448216 -0.4674941 0.3790383 -0.7849373
## med_low 0.3793852 -0.5409032 -0.4871632 -0.1210827 0.3134269 -0.1572023
## med_high -0.3541221 -0.3818558 -0.2874823 -0.2467060 0.1472214 0.0348942
## high -0.8677593 1.6379981 1.5139626 0.7806252 -0.8297808 0.8765519
## medv
## low 0.54744085
## med_low 0.02494892
## med_high 0.14654677
## high -0.64184370
##
## Coefficients of linear discriminants:
## LD1 LD2 LD3
## zn 0.10990805 0.766188216 -0.995049433
## indus -0.05176076 -0.123477729 0.031533164
## chas -0.07120442 -0.023889272 0.116907155
## nox 0.44937142 -0.771147396 -1.441766144
## rm -0.09144206 -0.130455189 -0.221950157
## age 0.24460741 -0.225639801 -0.134655367
## dis -0.09055557 -0.212480488 0.094620846
## rad 2.90499254 1.052508568 0.008616514
## tax 0.08009529 -0.117771732 0.704297122
## ptratio 0.14071054 -0.042921070 -0.388282334
## black -0.15771751 -0.009575611 0.118640858
## lstat 0.19028501 -0.204419173 0.364995745
## medv 0.18928126 -0.296978809 -0.194957866
##
## Proportion of trace:
## LD1 LD2 LD3
## 0.9442 0.0399 0.0159
# the function for lda biplot arrows
#(Stolen from Datacamp)
lda.arrows <- function(x, myscale = 1, arrow_heads = 0.1, color = "red", tex = 0.75, choices = c(1,2)){
heads <- coef(x)
arrows(x0 = 0, y0 = 0,
x1 = myscale * heads[,choices[1]],
y1 = myscale * heads[,choices[2]], col=color, length = arrow_heads)
text(myscale * heads[,choices], labels = row.names(heads),
cex = tex, col=color, pos=3)
}
# target classes as numeric
classes <- as.numeric(train$crime)
# plot the lda results
plot(lda.fit, dimen = 2,
col=classes,
pch=classes)
lda.arrows(lda.fit, myscale = 2)
# predict classes with test data
lda.pred <- predict(lda.fit,
newdata = test)
# cross tabulate the results
table(correct = correct,
predicted = lda.pred$class)
## predicted
## correct low med_low med_high high
## low 15 12 1 0
## med_low 2 10 8 0
## med_high 1 4 23 0
## high 0 0 0 26
table(correct = correct,
predicted = lda.pred$class) %>%
prop.table(2) %>% round(digits=2)
## predicted
## correct low med_low med_high high
## low 0.83 0.46 0.03 0.00
## med_low 0.11 0.38 0.25 0.00
## med_high 0.06 0.15 0.72 0.00
## high 0.00 0.00 0.00 1.00
#Reload boston
data(Boston)
boston_scaled <-
as.data.frame(scale(Boston))
#Calculate distances between observations
#I use Euclidean for no specific reason
#except that the km algorithm uses it
#by default
distances <- dist(boston_scaled)
summary(distances)
## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 0.1343 3.4625 4.8241 4.9111 6.1863 14.3970
#Identify correct number of clusters
#Use the WCSS for this purpose
k_max <- 15 #Arbitrary number
twcss <-
sapply(1:k_max,
function(k){
kmeans(
boston_scaled,k)$tot.withinss})
plot(x=1:k_max,y=twcss,type='l')
#2 seems appropriate
#Run k-means algorithm
km <- kmeans(boston_scaled,centers=2)
#Plot the data set in three parts
pairs(boston_scaled[
c(1,5,6,7,8,12,13,14)],
col=km$cluster)
km2 <- kmeans(boston_scaled,centers=3)
boston_scaled$km_clust <- km2$cluster
#LDA model (rename to avoid confusion
#in the next step)
lda.fit2 <-
lda(km_clust~., data=boston_scaled)
lda.fit2
## Call:
## lda(km_clust ~ ., data = boston_scaled)
##
## Prior probabilities of groups:
## 1 2 3
## 0.4664032 0.3241107 0.2094862
##
## Group means:
## crim zn indus chas nox rm
## 1 -0.3760908 -0.3417123 -0.296848 0.01127561 -0.3345884 -0.09228038
## 2 0.8046456 -0.4872402 1.117990 0.01575144 1.1253988 -0.46443119
## 3 -0.4075892 1.5146367 -1.068814 -0.04947434 -0.9962503 0.92400834
## age dis rad tax ptratio black
## 1 -0.02966623 0.05695857 -0.5803944 -0.6030198 -0.08691245 0.2863040
## 2 0.79737580 -0.85425848 1.2219249 1.2954050 0.60580719 -0.6407268
## 3 -1.16762641 1.19486951 -0.5983266 -0.6616391 -0.74378342 0.3538816
## lstat medv
## 1 -0.1801190 0.03577844
## 2 0.8719904 -0.68418954
## 3 -0.9480974 0.97889973
##
## Coefficients of linear discriminants:
## LD1 LD2
## crim -0.03134296 0.14880455
## zn -0.06381527 1.22350515
## indus 0.61086696 0.10402980
## chas 0.01953161 -0.03579238
## nox 1.00230143 0.70464917
## rm -0.16285767 0.44390394
## age -0.07220634 -0.59785382
## dis -0.04270475 0.45498614
## rad 0.71987743 0.02882054
## tax 0.98285440 0.70663319
## ptratio 0.22527977 0.15514668
## black -0.01693595 -0.03181845
## lstat 0.18274033 0.50122677
## medv -0.02892966 0.64244841
##
## Proportion of trace:
## LD1 LD2
## 0.8409 0.1591
classes <-
as.numeric(boston_scaled$km_clust)
# plot the lda results
plot(lda.fit2, dimen = 2,
col=classes,
pch=classes)
lda.arrows(lda.fit2, myscale = 2)
model_predictors <-
dplyr::select(train, -crime)
# check the dimensions
dim(model_predictors)
## [1] 404 13
dim(lda.fit$scaling)
## [1] 13 3
# matrix multiplication
matrix_product <-
as.matrix(model_predictors) %*% lda.fit$scaling
matrix_product <- as.data.frame(matrix_product)
library(plotly)
plot_ly(x = matrix_product$LD1,
y = matrix_product$LD2,
z = matrix_product$LD3,
type= 'scatter3d',
mode='markers',
color=train$crime)
#let's fit still another k-means
data(Boston)
boston_scaled <- as.data.frame(scale(Boston))
train <- boston_scaled[ind,]
km3 <- kmeans(train, centers=2)
plot_ly(x = matrix_product$LD1,
y = matrix_product$LD2,
z = matrix_product$LD3,
type= 'scatter3d',
mode='markers',
color=km3$cluster)
Harrison, D. & Rubinfeld, D.L. Hedonic housing prices and the demand for clean air. 1978. Journal of Environmental Economics and Management 5(1), 81-102.